Question for DUI pros

[pulicords]

If an offender's last intact of alcohol was approximately 60 minutes before contact with the officer and (at the time of contact) the subject's AB level was .10, approximately how long would it take for an average suspect's BA to test at .00?

Thanks!

[SCSO612]

If an offender's last intact of alcohol was approximately 60 minutes before contact with the officer and (at the time of contact) the subject's AB level was .10, approximately how long would it take for an average suspect's BA to test at .00?

Thanks!

That will depend on the subject's weight, food intake prior to the consumption, metabolism, and any medical conditions they may have.

[POPE]

The average person metabolizes alcohol at .015 grams per hour. So it's just simple math. It would would take that person approximately 6 hours 45 minutes from the time the test was given to reach .000

I'm not certified in reverse extrapolation but .015 is an average. Someone who is certified can take the person's height/weight/health status/ ect. and give a more accurate result.

[SRT936]

If we're talking strictly averages, 6 hours 45 minutes from the time they blew a .10. But as RDEP said, there are many factors that can push those numbers around a bit.

[pulicords]

Thanks for the assist!

[PhilipCal]

0.15% is the generally accepted average for the dissipation of alcohol from the system. That's exclusive of any other factors such as size, weight, etc.

[NYCTNT]

Im not a dwi guy by any means. Heck I forgot when I last did anything traffic related.. But can someone please post up the formula for this method of math?.

Thanks, I am a fail at math.

[CruiserClass]

Im not a dwi guy by any means. Heck I forgot when I last did anything traffic related.. But can someone please post up the formula for this method of math?.

Thanks, I am a fail at math.

You want BAC to equal 0, and it takes X hours at a drop of .15 each hour. Remembering a little bit of how to balance out equations, you start with B -(X*.15) = 0

B -(X*.15)= 0
add (X*.15) to both sides
B = x*.15
divide both sides by .15
B/.15 = X
is your final equation

B = starting BAC. Divide by .15 and the answer is the number of hours it will take for BAC to equal 0.

[SRT936]

You want BAC to equal 0, and it takes X hours at a drop of .15 each hour. Remembering a little bit of how to balance out equations, you start with B -(X*.15) = 0

B -(X*.15)= 0
add (X*.15) to both sides
B = x*.15
divide both sides by .15
B/.15 = X
is your final equation

B = starting BAC. Divide by .15 and the answer is the number of hours it will take for BAC to equal 0.

Change the .15 in the above formula to .015 and your good to go.

[Kieth M.]

As SRT said...get rid of .15 and replace it with .015 and the formula is the standard.